Question

In a certain place, the vertical component of earth?? magnetic field is 0.5 oersted and dip angle is $60^?$. The earth?? magnetic field at that place is

• A. $1$ oersted
• B. $\frac{\sqrt{3}}{2}$ oersted
• C. $2$ oersted
• D. $\frac{1}{\sqrt{3}}$ oersted

Answer 1

Answer: (D)

$\frac{1}{\sqrt{3}}$ oersted

Answer 2

Here, Vertical component of earth?? magnetic field, $V_{E}=0.5$ oersted Angle of dip, $\delta=60^{?}$ Earth?? magnetic field, $B_{E}=?$ As $sin\,\delta=\frac{V_{E}}{B_{E}}$ $\therefore B_{E}=\frac{V_{E}}{sin\,\delta }=\frac{0.5}{sin\,60^{?}}=\frac{0.5}{\left(\frac{\sqrt{3}}{2}\right)}=\frac{1}{\sqrt{3}}$ oersted