Question

In a certain electronic transition in the hydrogen atoms from an initial state (1) to a final state (2), the difference in the orbital radius (r1 – r2) is 24 times the first Bohr radius. Identify the transition.

• A. 5 → 1
• B. 25 → 1
• C. 8 → 3
• D. 6 → 5

Answer 1

Answer: (A)

5 → 1

Answer 2

r1 – r2 = 24 × (r1)H

$\frac{0.529 \times n_{1}^{2}}{1} - \frac{0.529 \times n_{2}^{2}}{1} = 24 \times 0.529$

$\therefore \left( n_{1}^{2} - n_{2}^{2} \right) = 24$