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Question: In a cell that utilizes the reaction \(\text{Z}\text{n}_{(s)}\text{ + 2}{\text{H}^{+}}_{(\text{aq})...

In a cell that utilizes the reaction

Zn(s) + 2H+(aq)Zn2+(aq) + H2(g),\text{Z}\text{n}_{(s)}\text{ + 2}{\text{H}^{+}}_{(\text{aq})} \rightarrow \text{Z}{\text{n}^{\text{2+}}}_{(\text{aq})}\text{ + }\text{H}_{2(g)}, addition of H2SO4 to cathode compartment will :

A

Lower the E and shift equilibrium to the left.

B

Lower the E and shift the equilibrium to the right.

C

Increase the E and shift the equilibrium to the right.

D

Increase the E and shift the equilibrium to the left.

Answer

Increase the E and shift the equilibrium to the right.

Explanation

Solution

Zn+2H+(aq)Zn2+(aq)+H2( g)\mathrm { Zn } + 2 \mathrm { H } ^ { + } { } _ { ( \mathrm { aq } ) } \longrightarrow \mathrm { Zn } ^ { 2 + } ( \mathrm { aq } ) + \mathrm { H } _ { 2 } ( \mathrm {~g} )

E=E00.05912logE = E^{0} - \frac{0.0591}{2}\logAdding H2SO4 means increasing H+ and therefore Ecell will increase and reaction will shift to forward direction