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Question: In a cell reaction \[Cu_{(s)} + 2Ag_{(aq)}^{+} \rightarrow Cu_{(aq)}^{2 +} + 2Ag_{(s)}\] \(Eº_{Cel...

In a cell reaction

Cu(s)+2Ag(aq)+→Cu(aq)2++2Ag(s)Cu_{(s)} + 2Ag_{(aq)}^{+} \rightarrow Cu_{(aq)}^{2 +} + 2Ag_{(s)}

EºCell=+0.46VEº_{Cell} = + 0.46V if the concentration of Cu2+Cu^{2 +} ions is doubled then EºCellEº_{Cell} will be

A

Doubled

B

Halved

C

Increased by four times

D

Unchanged

Answer

Unchanged

Explanation

Solution

EºCell=EºCathode−EºanodeEº_{Cell} = Eº_{Cathode} - Eº_{anode}

It will remain unchanged