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Physics Question on Semiconductor electronics: materials, devices and simple circuits

In a CECE amplifier β=50,RL=4 kΩ,R1=500 Ω\beta = 50, R_L = 4 \, k\Omega , R_1 = 500 \, \Omega . Power gain of the amplifier is

A

2×104 2 \times 10^4

B

2×102 2 \times 10^2

C

2×103 2 \times 10^3

D

2×101 2 \times 10^1

Answer

2×104 2 \times 10^4

Explanation

Solution

Here, β=50,RL=4kΩ=4000 Ω,R1=500 Ω\beta = 50, R_L = 4 k \Omega = 4000 \, \Omega , R_1 = 500 \, \Omega
Power gain =β2RLR1 = \beta^2 \frac{R_L}{R_1}
    =(50)2×4000500=2×104\, \, \, \, =(50)^2 \times \frac{4000}{500} = 2\times 10^4