Question

In a carnot engine, the temperature of reservoir is 527°C and that of sink is 200 K. If the work done by the engine when it transfers heat from reservoir to sink is 12000 kJ, the quantity of heat absorbed by the engine from reservoir is _____ $× 10^6$ J.

Answer 1

$η = 1 - \frac {T_2}{T_1}$

$= 1 - \frac {200}{800}$

$= \frac 34$

$∴ η =\frac {W}{Q_1}$

$⇒ \frac 34 = \frac {12000 \times 10^3}{Q_1}$

$⇒ Q_1 = 16 \times 10^6J$
Given that,the quantity of heat absorbed by the engine from reservoir is $x× 10^6$J.
on comparing, $x = 16$.

So, the answer is $16$.