Question

In a building there are $15$ bulbs of $45\, W, 15$ bulbs of $100\, W$, $15$ small fans of $10\, W$ and $2$ heaters of $1\, kW$. The voltage of electric main is $220\, V$. The minimum fuse capacity (rated value) of the building will be:

• A. $25\, A$
• B. $15\, A$
• C. $10\, A$
• D. $20\, A$

Answer 1

Answer: (D)

$20\, A$

Answer 2

$220 \,I = P = 15 ? 45 + 15 ? 100 + 15 ? 10 + 2 ? 10^{3}$
$I = \frac{4325}{220} = 19.66$
$I \simeq 20\,A$