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Question: In a box containing 100 eggs, 10 eggs are rotten. The probability that out of a sample of 5 eggs non...

In a box containing 100 eggs, 10 eggs are rotten. The probability that out of a sample of 5 eggs none is rotten if the sampling is with replacement is

A

(110)5\left( \frac { 1 } { 10 } \right) ^ { 5 }

B

(15)5\left( \frac { 1 } { 5 } \right) ^ { 5 }

C

(95)5\left( \frac { 9 } { 5 } \right) ^ { 5 }

D

(910)5\left( \frac { 9 } { 10 } \right) ^ { 5 }

Answer

(910)5\left( \frac { 9 } { 10 } \right) ^ { 5 }

Explanation

Solution

Let P(P ( fresh egg )=90100=910=p) = \frac { 90 } { 100 } = \frac { 9 } { 10 } = p

P(P ( rotten egg )=10100=110=q) = \frac { 10 } { 100 } = \frac { 1 } { 10 } = q ; n=5n = 5 r=5r = 5

So the probability that none egg is rotten

=5C5(910)5(110)0=(910)5= { } ^ { 5 } C _ { 5 } \left( \frac { 9 } { 10 } \right) ^ { 5 } \cdot \left( \frac { 1 } { 10 } \right) ^ { 0 } = \left( \frac { 9 } { 10 } \right) ^ { 5 }.