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Question

Mathematics Question on mathematical reasoning

In a boolean algebra BB with respect to +' +' and .,'.', xx' denotes the negation of xBx\in B . Then

A

xx=1x - x' = 1 and xx=1x \cdot x' = 1

B

x+x=1x + x' = 1 and xx=0x \cdot x' = 0

C

x+x=0x + x' = 0 and xx=1x \cdot x' = 1

D

x+x=0x + x' = 0 and xx=0x \cdot x' = 0

Answer

x+x=1x + x' = 1 and xx=0x \cdot x' = 0

Explanation

Solution

By the complement law, x+x=1x+x=1 and x.x=0x.x=0