Question

In a beryllium atom, if a₀ be the radius of the first orbit, then the radius of the second orbit will be in general.

• A. $na_{0}$
• B. $a_{0}$
• C. $n^{2}a_{0}$
• D. $\frac{a_{0}}{n^{2}}$

Answer 1

Answer: (C)

$n^{2}a_{0}$

Answer 2

$r \propto n^{2}$ ⇒ $r_{n} = n^{2}a_{0}$ $(\because r_{1} = a_{0})$