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Question: In a ∆ABC,<img src="https://cdn.pureessence.tech/canvas_342.png?top_left_x=967&top_left_y=300&width=...

In a ∆ABC, and the side

a = 2,then area of the triangle is

A

1

B

2

C

32\frac { \sqrt { 3 } } { 2 }

D

3\sqrt { 3 }

Answer

3\sqrt { 3 }

Explanation

Solution

=cos⁡Bb\frac { \cos B } { b }=

==

⇒ tan A = tan B = tan C

⇒ A = B = C (equilateral triangle)

∴ ∆ = 34\frac { \sqrt { 3 } } { 4 }(side)2 = 34\frac { \sqrt { 3 } } { 4 }(2)2 = 3\sqrt { 3 }