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Question: In a ∆ABC, if 2s = a + b + c and (s– b) (s –c) = x sin<sup>2</sup>\(\frac{A}{2}\), then x =...

In a ∆ABC, if 2s = a + b + c and (s– b) (s –c) = x sin2A2\frac{A}{2}, then x =

A

bc

B

ca

C

ab

D

abc

Answer

bc

Explanation

Solution

(s – b) (s – c) = x sin2 A2\frac{A}{2}

⇒ (s – b) (s – c) = x (sb)(sc)bc\frac{(s - b)(s - c)}{bc}

⇒ x = bc