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Question

Physics Question on carnot cycle

In 1st case, Carnot engine operates between temperatures 300 K and 100 K. In 2nd case, as shown in the figure, a combination of two engines is used. The efficiency of this combination (in 2nd case) will be:

Fig.

A

Same as the 1st case

B

Always greater than the 1st case

C

Always less than the 1st case

D

May increase or decrease with respect to the 1st case

Answer

Always less than the 1st case

Explanation

Solution

The correct answer is (C) : Always less than the 1st case
ηnet=W1+W2Q1η_{net} = \frac{W_1+W_2}{Q_1}
ηnet=W1Q1+W2Q1η_{net} = \frac{W_1}{Q_1}+\frac{W_2}{Q_1}
ηnet=η1+W2Q2×Q2Q1η_{net} = η_1+\frac{W_2}{Q_2}×\frac{Q_2}{Q_1}
ηnet=η1+(η2)(1η1)η_{net} = η_1+(η_2)(1-η_1)
1η1<11-η_1<1
ηnet<η1+η2⇒ η_{ne}t<η_1+η_2