(\integral \_ { 2 } ^ { 4 } x \sqrt { 6 - x })dx = ……. | MATH - FUNDAMENTAL DEFINITE INTEGRATION, DEFINITE INTEGRATION BY SUBSTITUTION | SolveeIt | Solveeit

Today, August 18

Question

$\int _ { 2 } ^ { 4 } x \sqrt { 6 - x }$ dx = …….

A

$\frac { 32 } { 5 } ( 3 + \sqrt { 2 } )$

B

$\frac { 32 } { 5 } ( 3 - \sqrt { 2 } )$

C

$\frac { 16 } { 5 } ( 3 - \sqrt { 2 } )$

D

None of these

Answer

$\frac { 32 } { 5 } ( 3 - \sqrt { 2 } )$

Explanation

Solution

Put x ® 6 – x