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Question

Question: <img src="https://cdn.pureessence.tech/canvas_343.png?top_left_x=0&top_left_y=1502&width=300&height=...

equals

A

p/2

B

p/4

C

0

D

1

Answer

1

Explanation

Solution

Put sin–1 x = t, then

\ I == + [sin⁡x]0π/2[ \sin \mathrm { x } ] _ { 0 } ^ { \pi / 2 } = 1