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Question: \(\int _ { 0 } ^ { \pi / 2 } \frac { \sqrt { \cot x } } { \sqrt { \cot x } + \sqrt { \tan x } } d x\...

∫0π/2cot⁡xcot⁡x+tan⁡xdx\int _ { 0 } ^ { \pi / 2 } \frac { \sqrt { \cot x } } { \sqrt { \cot x } + \sqrt { \tan x } } d x=

A

1

B

–1

C

π2\frac { \pi } { 2 }

D

π4\frac { \pi } { 4 }

Answer

π4\frac { \pi } { 4 }

Explanation

Solution

Direct result = π4\frac { \pi } { 4 }