Question

On acid hydrolysis of above disacharide, we get

• A. Two moles of glucose
• B. One mole of glucose
• C. One mole of galactose
• D. One mole of glucose and one mole of galactose

Answer 1

Answer: (D)

One mole of glucose and one mole of galactose

Answer 2

$\mathrm { H } ^ { \oplus } / \mathrm { H } _ { 2 } \mathrm { O }$

Galactose (1 mole) H2O (– MeOH)

Glucose (1 mole)