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Question: <img src="https://cdn.pureessence.tech/packed_images/canvas_681.png?x=0&y=286&width=241&height=300" ...

+ CH2 = CHCH2Cl → (ii) H2O2/OH−(i) BH3, THF \xrightarrow [ \text { (ii) } \mathrm { H } _ { 2 } \mathrm { O } _ { 2 } / \mathrm { OH } ^ { - } ] { \text {(i) } \mathrm { BH } _ { 3 } , \text { THF } } →HF,Δ\xrightarrow { \mathrm { HF } , \Delta } P

The compound ‘P’ is

A
B
C
D
Answer
Explanation

Solution

+ CH2 = CHCH2Cl