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Question: \(0.6\) mole of \(\mathrm { PCl } _ { 5 }\), \(0.3\) mole of \(\mathrm { PCl } _ { 3 }\)and \(0.5\)m...

0.60.6 mole of PCl5\mathrm { PCl } _ { 5 }, 0.30.3 mole of PCl3\mathrm { PCl } _ { 3 }and 0.50.5mole of Cl2\mathrm { Cl } _ { 2 }are taken in a 1 L flask to obtain the following equilibrium:

If the equilibrium constant for the reaction is 0.20.2Predict the direction of the reaction.

A

Forward direction

B

Backward direction

C

Direction of the reaction cannot be predicted

D

Reaction does not move in any direction.

Answer

Backward direction

Explanation

Solution

: PCl3( g)+Cl2( g)\mathrm { PCl } _ { 3 ( \mathrm {~g} ) } + \mathrm { Cl } _ { 2 ( \mathrm {~g} ) }

Qc=0.5×0.30.6=0.25Q _ { c } = \frac { 0.5 \times 0.3 } { 0.6 } = 0.25

Since Qc>KcQ _ { c } > K _ { c } reaction will proceed in backward direction.