If z2 = |z|2, then | MATH - CONJUGATE, MODULUS AND ARGUMENT OF COMPLEX NUMBERS | SolveeIt | Solveeit

Today, August 24

Question

If z² = |z|², then

A

Z is purely imaginary

B

Z is purely real

C

Z can be any complex number

D

None of the above

Answer

Z is purely real

Explanation

Solution

Sol. z² = |z|² ; z² = z $\bar{z}$ ; z = $\bar{z}$ , so z is purely real