If (|z\_{2}|), then (|z\_{1} + z\_{2}|) | MATH - CONJUGATE, MODULUS AND ARGUMENT OF COMPLEX NUMBERS | SolveeIt | Solveeit

Today, August 18

Question

If $|z_{2}|$ , then $|z_{1} + z_{2}|$

A

$|z_{1} + z_{2}| + |z_{1} - z_{2}|$

B

$\left| \frac{1}{2}(z_{1} + z_{2}) + \sqrt{z_{1}z_{2}} \right| + \left| \frac{1}{2}(z_{1} + z_{2}) - \sqrt{z_{1}z_{2}} \right|$

C

$|z_{1} + z_{2}|$

D

$|z_{1} - z_{2}|$

Answer

$\left| \frac{1}{2}(z_{1} + z_{2}) + \sqrt{z_{1}z_{2}} \right| + \left| \frac{1}{2}(z_{1} + z_{2}) - \sqrt{z_{1}z_{2}} \right|$

Explanation

Solution

It is a fundamental concept.