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Question

Question: If \(|z_{1} - z_{2}|\) then....

If ∣z1−z2∣|z_{1} - z_{2}| then.

A

∣z1∣+∣z2∣|z_{1}| + |z_{2}|

B

∣z1∣−∣z2∣|z_{1}| - |z_{2}|

C

∣∣z1∣−∣z2∣∣||z_{1}| - |z_{2}||

D

∣z1+z2∣=∣z1−z2∣|z_{1} + z_{2}| = |z_{1} - z_{2}|

Answer

∣z1∣−∣z2∣|z_{1}| - |z_{2}|

Explanation

Solution

y=2aby = 2ab

−x−iy=−(a2−b2)−2iab=b2−a2−2iab\sqrt{- x - iy} = \sqrt{- (a^{2} - b^{2}) - 2iab} = \sqrt{b^{2} - a^{2} - 2iab}and

=(b−ia)2=±(b−ia)= \sqrt{(b - ia)^{2}} = \pm (b - ia)

3−4i=x+iy\sqrt{3 - 4i} = x + iy.