Question

If z = x + iy satisfies | z | – 2 = 0 and |z – i| – | z + 5i| = 0, then

• A. x + 2y – 4 = 0
• B. x2 + y – 4 = 0
• C. x + 2y + 4 = 0
• D. x2 – y + 3 = 0

Answer 1

Answer: (C)

x + 2y + 4 = 0

Answer 2

The correct answer is (C) : x + 2y + 4 = 0
|z-i| = |z+5i|
Thereafter, z lies on ⊥r bisector of (0, 1) and (0, –5)
i.e., line y = –2
as |z| = 2
⇒ z = –2i
x = 0 and y = –2Hence, x + 2y + 4 = 0