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Question: If z is a complex number satisfying the equation\[\left| {z + i} \right| + \left| {z - i} \right| = ...

If z is a complex number satisfying the equationz+i+zi=8\left| {z + i} \right| + \left| {z - i} \right| = 8, on the complex plane then maximum value of z\left| z \right| is
A.2
B.4
C.6
D.8

Explanation

Solution

Hint : Complex number is a number generally represented as z=a+ibz = a + ib, where aa and bb is real number represented on real axis whereas ii is an imaginary unit represented on imaginary axis whose value is i=1i = \sqrt { - 1} . Modulus of a complex number is length of line segment on real and imaginary axis generally denoted by z\left| z \right| whereas angle subtended by line segment on real axis is argument of matrix denoted by argument (z) calculated by trigonometric value. Argument of complex numbers is denoted by arg(z)=θ=tan1ba\arg (z) = \theta = {\tan ^{ - 1}}\dfrac{b}{a}.

Complete step-by-step answer :
In this question, we need to determine the maximum value of z\left| z \right| such that z+i+zi=8\left| {z + i} \right| + \left| {z - i} \right| = 8 have to be satisfied. For this we will use the properties of the complex numbers as discussed above.
z+i+zi=8(i)\left| {z + i} \right| + \left| {z - i} \right| = 8 - - (i)
This equation can be written as
z(i)+zi=8(ii)\left| {z - \left( { - i} \right)} \right| + \left| {z - i} \right| = 8 - - (ii)
We know imaginary unit iiis represented on a plane as

Now it is given that a point z is on the plane whose sum of distance from points ii and i - i is given as 8 as shown in the diagram below

We know the equation of the locus from point P for the sum of distance between two fixed points is constant PA+PB=2a(iii)PA + PB = 2a - - (iii)and this constant form an ellipse

Now if we compare equation (iii) with the equation (i), we can say

2a=8 a=4  2a = 8 \\\ a = 4 \\\

Where a=4a = 4 is the maximum value from which the ellipse pass, hence we can say the maximum value of z\left| z \right| is =4 = 4

Note : Complex numbers are always written in the form of z=a+ibz = a + ib where aa and bb are real numbers whereas iibeing imaginary part. We can convert a degree into radian by multiplying it by π180\dfrac{\pi }{{180}}. Argument of complex numbers is denoted by arg(z)=θ=tan1ba\arg (z) = \theta = {\tan ^{ - 1}}\dfrac{b}{a}.