Question
Question: If z is a complex number satisfying the equation\[\left| {z + i} \right| + \left| {z - i} \right| = ...
If z is a complex number satisfying the equation∣z+i∣+∣z−i∣=8, on the complex plane then maximum value of ∣z∣ is
A.2
B.4
C.6
D.8
Solution
Hint : Complex number is a number generally represented as z=a+ib, where a and b is real number represented on real axis whereas i is an imaginary unit represented on imaginary axis whose value is i=−1. Modulus of a complex number is length of line segment on real and imaginary axis generally denoted by ∣z∣ whereas angle subtended by line segment on real axis is argument of matrix denoted by argument (z) calculated by trigonometric value. Argument of complex numbers is denoted by arg(z)=θ=tan−1ab.
Complete step-by-step answer :
In this question, we need to determine the maximum value of ∣z∣ such that ∣z+i∣+∣z−i∣=8 have to be satisfied. For this we will use the properties of the complex numbers as discussed above.
∣z+i∣+∣z−i∣=8−−(i)
This equation can be written as
∣z−(−i)∣+∣z−i∣=8−−(ii)
We know imaginary unit iis represented on a plane as
Now it is given that a point z is on the plane whose sum of distance from points i and −i is given as 8 as shown in the diagram below
We know the equation of the locus from point P for the sum of distance between two fixed points is constant PA+PB=2a−−(iii)and this constant form an ellipse
Now if we compare equation (iii) with the equation (i), we can say
Where a=4 is the maximum value from which the ellipse pass, hence we can say the maximum value of ∣z∣ is =4
Note : Complex numbers are always written in the form of z=a+ib where a and b are real numbers whereas ibeing imaginary part. We can convert a degree into radian by multiplying it by 180π. Argument of complex numbers is denoted by arg(z)=θ=tan−1ab.