Question
Question: If \[z=\dfrac{4}{1-i}\] then bar z (\[\bar{z}\]) is equal to (where bar z is complex conjugate of z)...
If z=1−i4 then bar z (zˉ) is equal to (where bar z is complex conjugate of z):
(a)2(1+i)
(b)1+i
(c)1−i2
(d)1+i4
Solution
The value of bar z (zˉ) is equal tozˉ=x−iy. Where bar z (zˉ) is the conjugate value of the complex term which is mentioned in the question as z. We will first assume our z = x + iy, with respect to which we will find the bar z (zˉ).
Complete step by step solution:
The value of z that has been mentioned the in the question isz=1−i4, as we can see that the term that has been mentioned is a complex term as it has term (i) in it and we know that square root = positive number, and we also know that square root will be a real number until the number is positive, i.e. square root = positive number, and as we can see that the number inside the square root is negative i.e. square root = positive number we can easily say that the square root of this number will have imaginary roots and hence we will have a complex number that is mentioned in the question.
Now when we see the question we can see that the equation that has been mentioned in the question as z=1−i4, we can also write it as z = x +iy, and as explained above that bar z (zˉ) is the conjugate of the complex number z, we can write the complex conjugate bar z (zˉ) as zˉ=x−iy
Now as we can see that the value of y in the complex number is negative, we will substitute the same in the complex conjugate of z which is bar z (zˉ) and we finally get the value of bar z (zˉ) as zˉ=1+i4
From the options as stated above in the question we can easily say that option (d) is correct which is zˉ=1+i4.
Note: The common mistake that is done in these type of questions is to how to calculate the value of bar z (zˉ), where the value of bar z (zˉ) is zˉ=x−iy whenever the value of z = x +iy as we know that the bar z (zˉ) is the complex conjugate of z.