Question
Question: If \(z\) be a complex number, then the minimum value of \(\left| z-7 \right|+\left| z \right|\) is ...
If z be a complex number, then the minimum value of ∣z−7∣+∣z∣ is
(a) 23−1
(b) −7
(c) 27+2
(d) 7
Solution
Hint: Use the property of modulus of complex number,∣z1∣+∣z2∣≥∣z1+z2∣≥∣z1−z2∣, assume z1=z−7 and z2=z. This property of modulus of complex numbers is also called triangle inequality property.
Complete answer:
A complex number is a number that can be expressed in the form of a+ib, where a and b are real numbers and i is the solution of the equation x2=−1. Because no real number satisfies this equation, iis called an imaginary number. For the complex number, a+ib, a is called the real part, and b is called the imaginary part. Complex numbers allow solutions to certain equations that have no solutions in real numbers. For any complex number, z=x+iy, the absolute value or modulus of z is denoted ∣z∣ and is defined by: ∣z∣=x2+y2, where x and y are the real and imaginary part of z respectively. When the imaginary part y is zero, this coincides with the definition of the absolute value of the real number x.
Now, we come to the question. We have to find the minimum value of complex function given by ∣z−7∣+∣z∣. We know that using triangle inequality we have,∣z1∣+∣z2∣≥∣z1+z2∣≥∣z1−z2∣, so, minimum value of the function ∣z1∣+∣z2∣ is ∣z1−z2∣.
Therefore, minimum of ∣z−7∣+∣z∣ =∣(z−7)−z∣=∣−7∣=7. Hence, option (d) is the correct answer.
Note: Since modulus of any number is always positive so, ∣−7∣=7. Don’t get confused that if inside modulus there is a negative number then if we remove modulus the number remains negative. It will always be positive. In other words, we can also say that minima occurs when z becomes zero.