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Question

Mathematics Question on Complex Numbers and Quadratic Equations

If zz be a complex number satisfying Re(z)+Im(z)=4,\left|Re\left(z\right)\right|+\left|Im\left(z\right)\right|=4, then z|z| cannot be :

A

7\sqrt{7}

B

172\sqrt{\frac{17}{2}}

C

10\sqrt{10}

D

8\sqrt{8}

Answer

7\sqrt{7}

Explanation

Solution

z=x+iyx+y=4z = x + iy \quad\quad|x| + |y| = 4
z=x2+y2zmin=8&zmax=4=16\left|z\right| = \sqrt{x^{2}+y^{2}} \Rightarrow \left|z\right|_{min} = \sqrt{8} \,\& \,\left|z\right|_{max} = 4 = \sqrt{16}
So |z| cannot be 7\sqrt{7}