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Question

Mathematics Question on Algebra of Complex Numbers

If z=2+3iz = 2 + 3i, then z5+(z)5z^5 + (\overline{z})^5 is equal to:

A

244

B

224

C

245

D

265

Answer

244

Explanation

Solution

z=(2+3i)z = (2 + 3i)
z5=(2+3i)((2+3i)2)2z^5 = (2 + 3i)((2 + 3i)^2)^2
=(2+3i)(5+12i)2= (2 + 3i) (-5 + 12i)^2
=(2+3i)(119120i)= (2 + 3i)(-119 – 120i)
=238240i357i\+360= – 238 – 240i – 357i \+ 360
=122597i= 122 – 597i
z5=122+597i\overline{z}^5 = 122 + 597i
z5+z5=244z^5 + \overline{z}^5 = 244
So, the correct option is (A): 244