Question
Mathematics Question on Maxima and Minima
If z=(11+2i−5i1−2i−35+3i5i5−3i7) then (i=−1)
A
(A) z is purely real
B
(B) z is purely imaginary
C
(C) z+z¯=0
D
(D) (z−z¯) i is purely imaginary
Answer
(A) z is purely real
Explanation
Solution
Explanation:
If z=(11+2i−5i1−2i−35+3i5i5−3i7) then (i=−1)