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Question: If \({z_1},{z_2}\) and \({z_3}\) are complex numbers such that \(\left| {{z_1}} \right| = \left| {{z...

If z1,z2{z_1},{z_2} and z3{z_3} are complex numbers such that z1=z2=z3=1z1+1z2+1z3=1\left| {{z_1}} \right| = \left| {{z_2}} \right| = \left| {{z_3}} \right| = \left| {\dfrac{1}{{{z_1}}} + \dfrac{1}{{{z_2}}} + \dfrac{1}{{{z_3}}}} \right| = 1 then z1+z2+z3\left| {{z_1} + {z_2} + {z_3}} \right|is :
A. Equal to 11
B. Less than 11
C. Greater than 33
D. Equal to 33

Explanation

Solution

For solving this particular problem, we first take the given expression that is z1=z2=z3=1|{z_1}| = |{z_2}| = |{z_3}| = 1 , then we will square this expression . then we will use the relation we have as z12=z1z1{\left| {{z_1}} \right|^2} = {z_1}\overline {{z_1}} , multiplication of the complex number with the conjugate of the complex number we get magnitude which represents the distance of the complex number from the origin. Then we will get, z1z1=z2z2=z3z3=1{z_1}\overline {{z_1}} = {z_2}\overline {{z_2}} = {z_3}\overline {{z_3}} = 1 , then substitute the result in the equation 1z1+1z2+1z3=1\left| {\dfrac{1}{{{z_1}}} + \dfrac{1}{{{z_2}}} + \dfrac{1}{{{z_3}}}} \right| = 1 , and try to manipulate this equation to get the value of z1+z2+z3\left| {{z_1} + {z_2} + {z_3}} \right| .

Complete solution step by step:
Now we know that,
z1=z2=z3=1|{z_1}| = |{z_2}| = |{z_3}| = 1 (given)
Now Squaring the given expression, we get the following ,
z12=z22=z32=12......(1)|{z_1}{|^2} = |{z_2}{|^2} = |{z_3}{|^2} = {1^2}......(1)
Now we know that z12=z1z1{\left| {{z_1}} \right|^2} = {z_1}\overline {{z_1}} , multiplication of the
complex number with the conjugate of the complex number we get magnitude which represents the distance of the complex number from the origin. we get, z1 overlinez1=z2z2=z3z3=1{z_1}\ overline {{z_1}} = {z_2}\overline {{z_2}} = {z_3}\overline {{z_3}} = 1 ,
Now,
1=1z1+1z2+1z3 =z1z1z1+z2z2z2+z3z3z3 =z1+z2+z3 =z1+z2+z3 =z1+z2+z3 =1  \Rightarrow 1 = \left| {\dfrac{1}{{{z_1}}} + \dfrac{1}{{{z_2}}} + \dfrac{1}{{{z_3}}}} \right| \\\ = \left| {\dfrac{{{z_1}\overline {{z_1}} }}{{{z_1}}} + \dfrac{{{z_2}\overline {{z_2}} }}{{{z_2}}} + \dfrac{{{z_3}\overline {{z_3}} }}{{{z_3}}}} \right| \\\ = \left| {\overline {{z_1}} + \overline {{z_2}} + \overline {{z_3}} } \right| \\\ = \overline {\left| {{z_1} + {z_2} + {z_3}} \right|} \\\ = \left| {{z_1} + {z_2} + {z_3}} \right| \\\ = 1 \\\
Hence we can say that the value of z1+z2+z3\left| {{z_1} + {z_2} + {z_3}} \right| is equal to one.
Therefore, option A is correct.

Formula Used:
For solving this particular solution ,we used the following relationship ,
z12=z1z1{\left| {{z_1}} \right|^2} = {z_1}\overline {{z_1}} , here z1\overline {{z_1}} means the
conjugate of z1{z_1} .

Note: As we know that z=x+yiz = x + yi , which is the representation of the complex number. And z=xyiz = x - yi , is the conjugate of the complex number. Now multiplication of the complex number with the conjugate of the complex number we get magnitude which represents the distance of the complex number from the origin.