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Question: If z = 1 + i tana, where p\<a\<\(\frac{3\pi}{2}\), then \|z\| is equal to –...

If z = 1 + i tana, where p<a<3π2\frac{3\pi}{2}, then |z| is equal to –

A

seca

B

cos a

C

– sec a

D

cosec a

Answer

– sec a

Explanation

Solution

Sol. | z | = 1+tan⁡2α\sqrt{1 + \tan^{2}\alpha} = |sec a |

= – sec a (Q p < a < 3a/2)