Question
Question: If \(z=1+2i\), then find the value of \({{z}^{2}}\)....
If z=1+2i, then find the value of z2.
Solution
Hint: To evaluate the value of the given algebraic expression, substitute the value of the given complex number in the given expression, and simplify it using the algebraic identity (a+b)2=a2+b2+2ab. Calculate the value of the expression using the fact that i is a root of unity.
Complete step-by-step solution -
We know that z=1+2i. We have to calculate the value of z2.
We observe that z=1+2i is a complex number while z2 is an algebraic expression. We will evaluate the value of this expression at z=1+2i.
To do so, we will substitute z=1+2i in the given expression and simplify it using the algebraic identity (a+b)2=a2+b2+2ab.
Thus, we have z2=(1+2i)2.
Simplifying the above expression using the algebraic identity, we have z2=(1+2i)2=12+(2i)2+2(2i)(1)
So, we have z2=(1+2i)2=12+(2i)2+2(1)(2i)=1+4i2+4i.
We know that i=−1. Thus, we have i2=−1.
Simplifying the above expression, we have z2=(1+2i)2=12+(2i)2+2(1)(2i)=1+4i2+4i=1+4(−1)+4i.
We can further solve the above expression to write it as z2=(1+2i)2=12+(2i)2+2(1)(2i)=1+4i2+4i=1+4(−1)+4i=1−4+4i=−3+4i.
Hence, the value of z2 when z=1+2i is −3+4i.
Note: We must keep in mind that i=−1 is the root of unity. It is a solution to the equation x2+1=0. Thus, we have i2=(−1)2=−1. We can write any complex number in the form a+ib, where ib is the imaginary part and a is the real part. We can’t solve this question without using the algebraic identity.