Question
Question: If \(|z| - z = 1 + 2i\)and \(2 - \frac{3}{2}i\)then \(\frac{3}{2} + 2i\) is....
If ∣z∣−z=1+2iand 2−23ithen 23+2i is.
A
Purely real
B
Purely imaginary
C
Zero
D
Undefined
Answer
Purely imaginary
Explanation
Solution
(z1)−arg(z2)=0 .....(i)
Now, ∣z1+z2∣=∣z1∣+∣z2∣⇒z1,z2
∴argz1=argz2⇒argz1−argz2=0z=5−3i [by equation (i)]
Hence, r(cosθ+isinθ)=5−3iis purely imaginary.