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Question: If Young's modulus of iron is \(2 \times 10 ^ { 11 } \mathrm {~N} / \mathrm { m } ^ { 2 }\) and the ...

If Young's modulus of iron is 2×1011 N/m22 \times 10 ^ { 11 } \mathrm {~N} / \mathrm { m } ^ { 2 } and the interatomic spacing between two molecules is 3×10−103 \times 10 ^ { - 10 }metre, the interatomic force constant is

A

60 N/m

B

120 N/m

C

30 N/m

D

180 N/m

Answer

60 N/m

Explanation

Solution

Interatomic force constant K=Y×r0K = Y \times r _ { 0 } =2×1011×3×10−10=60 N/m= 2 \times 10 ^ { 11 } \times 3 \times 10 ^ { - 10 } = 60 \mathrm {~N} / \mathrm { m }