Question

If y = tan^–1$\left( \frac{\log(e/x^{3})}{\log(ex^{3})} \right)$+ tan^–1$\left( \frac{\log(e^{4}x^{3})}{\log(e/x^{12})} \right)$, then $\frac{d^{2}y}{dx^{2}}$is equal to-

• A. 1
• B. 0
• C. –1
• D. None of these

Answer 1

Answer: (B)

0

Answer 2

y = sin^–1 $\left( \frac{1 - 3\log x}{1 + 3\log x} \right)$+ tan^–1 $\left( \frac{4 + 3\log\pi}{1 - 12\log x} \right)$

y = tan^–1 (1) – tan^–1 |3 tan x| + tan^–1 (4)+ tan^–1(3 tan θ)

y = tan^–1 (1) + tan^–1 4

$\frac{dy}{dx}$= 0 ⇒ $\frac{d^{2}y}{dx^{2}}$= 0