Question
Mathematics Question on Derivatives
If y=logx+logx+logx+logx+.....+ then dxdy is :
A
y(2x−1)1
B
xy−11
C
x(2y−1)1
D
x(y−1)1
Answer
x(2y−1)1
Explanation
Solution
The correct option is (C) :x(2y−1)1.
If y=logx+logx+logx+logx+.....+ then dxdy is :
y(2x−1)1
xy−11
x(2y−1)1
x(y−1)1
x(2y−1)1
The correct option is (C) :x(2y−1)1.