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Question: If \(y = \sin (2x)\) , then \(\dfrac{{dy}}{{dx}}\) is equal to Choose the correct option from the ...

If y=sin(2x)y = \sin (2x) , then dydx\dfrac{{dy}}{{dx}} is equal to
Choose the correct option from the following options:
A. 2cos(2x)2\cos (2x)
B. 2cos(x)2\cos (x)
C. 2sin(x)2\sin (x)
D. 2sin(2x)2\sin (2x)

Explanation

Solution

For solving this particular question we must know that Differentiation of trigonometric function sine of variable xx is equal to cosine of variable xx , and differentiation of sinax=acosax\sin ax = a\cos ax where aa is any constant and xx is the variable .

Complete solution step by step:
It is given it the question that ,
y=sin2xy = \sin 2x (given)
Now , differentiate on both sides with respect to xx , we will get ,
dydx=ddx(sin2x)\dfrac{{dy}}{{dx}} = \dfrac{d}{{dx}}(\sin 2x)
dydx=cos(2x).2\Rightarrow \dfrac{{dy}}{{dx}} = \cos (2x).2 (since differentiation of sinax=acosax\sin ax = a\cos ax )
=2cos2x= 2\cos 2x
Therefore , dydx=2cos2x\dfrac{{dy}}{{dx}} = 2\cos 2x .
And we can say that option A is the correct option.
Formula used: For solving this particular question we used ,
ddx(sinax)=acosax\dfrac{d}{{dx}}(\sin ax) = a\cos ax ,where aais any constant and xx is the variable .
Differentiation of trigonometric function sine of variable xx is equal to cosine of variable xx .

Additional Information:
Differentiation is the essence of Calculus. A derivative is defined because the instantaneous rate of change in function supported one in every of its variables. it's just like finding the slope of a tangent to the function at some extent. we've got following rules in differentiation ,
• Sum and Difference rule that claims (u(x) ± v(x))’=u'(x)±v'(x)
• Product rule that says (u(x) × v(x))’=u′(x)×v(x)+u(x)×v′(x)
• Quotient Rule that claims (u(x)/v(x))’ =(u′(x)×v(x)−u(x)×v′(x))/(v(x))2
• Chain Rule that says dy(u(x))/dx = dy/du × du/dx

Note: The differentiation of a function f(x)f(x) is represented as f(x)f'(x) . If f(x)=yf(x) = y, then f(x)=dydxf'(x) =\dfrac{{dy}}{{dx}} , which means yy is differentiated with respect to xx Differentiation of trigonometric function sine of variable xx is equal to cosine of variable xx , and differentiation of sinax=acosax\sin ax = a\cos ax where aa is any constant and xx is the variable