Question
Question: If \(y = \sin (2x)\) , then \(\dfrac{{dy}}{{dx}}\) is equal to Choose the correct option from the ...
If y=sin(2x) , then dxdy is equal to
Choose the correct option from the following options:
A. 2cos(2x)
B. 2cos(x)
C. 2sin(x)
D. 2sin(2x)
Solution
For solving this particular question we must know that Differentiation of trigonometric function sine of variable x is equal to cosine of variable x , and differentiation of sinax=acosax where a is any constant and x is the variable .
Complete solution step by step:
It is given it the question that ,
y=sin2x (given)
Now , differentiate on both sides with respect to x , we will get ,
dxdy=dxd(sin2x)
⇒dxdy=cos(2x).2 (since differentiation of sinax=acosax )
=2cos2x
Therefore , dxdy=2cos2x .
And we can say that option A is the correct option.
Formula used: For solving this particular question we used ,
dxd(sinax)=acosax ,where ais any constant and x is the variable .
Differentiation of trigonometric function sine of variable x is equal to cosine of variable x .
Additional Information:
Differentiation is the essence of Calculus. A derivative is defined because the instantaneous rate of change in function supported one in every of its variables. it's just like finding the slope of a tangent to the function at some extent. we've got following rules in differentiation ,
• Sum and Difference rule that claims (u(x) ± v(x))’=u'(x)±v'(x)
• Product rule that says (u(x) × v(x))’=u′(x)×v(x)+u(x)×v′(x)
• Quotient Rule that claims (u(x)/v(x))’ =(u′(x)×v(x)−u(x)×v′(x))/(v(x))2
• Chain Rule that says dy(u(x))/dx = dy/du × du/dx
Note: The differentiation of a function f(x) is represented as f′(x) . If f(x)=y, then f′(x)=dxdy , which means y is differentiated with respect to x Differentiation of trigonometric function sine of variable x is equal to cosine of variable x , and differentiation of sinax=acosax where a is any constant and x is the variable