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Question

Mathematics Question on Differential Equations

If y=sin1xy=sin^{-1}x and (1x2)d2ydx2xdydx=K(1-x^2)\frac{d^2y}{dx^2} -x \frac{dy}{dx}=K,then value of K is:

A

2

B

12\frac12

C

0

D

1

Answer

0

Explanation

Solution

The correct option is (C): 0