Solveeit Logo
Login

Question

Mathematics Question on Inverse Trigonometric Functions

If y=sin⁡−112(1+x+1−x)y=\sin^{-1}\frac{1}{2}(\sqrt{1+x}+\sqrt{1-x}) then y' =

A

121−x2\frac{1}{2\sqrt{1-x^2}}

B

−121−x2\frac{-1}{2\sqrt{1-x^2}}

C

121+x2\frac{1}{2\sqrt{1+x^2}}

D

−121+x2\frac{-1}{2\sqrt{1+x^2}}

Answer

−121−x2\frac{-1}{2\sqrt{1-x^2}}

Explanation

Solution

The correct option is B) : −121−x2\frac{-1}{2\sqrt{1-x^2}}.