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Question: If y = mx divides the area bounded by lines x = 0, y = 0, x = 3/2 and the curves y = 1 + 4x – x<sup...

If y = mx divides the area bounded by lines x = 0, y = 0,

x = 3/2 and the curves y = 1 + 4x – x2 in two equal parts, then m is equal to -

A

13/8

B

13/4

C

13/6

D

None of these

Answer

13/6

Explanation

Solution

Equation of the given curve is (x –2)2 = – (y – 5) which is a parabola given

area = =

=[x+2x2x33]03/2\left[ x + 2 x ^ { 2 } - \frac { x ^ { 3 } } { 3 } \right] _ { 0 } ^ { 3 / 2 } = 3/2 + 9/2 –9/18 = 39/8 Also A¢ =

= m2[x2]03/2\frac { \mathrm { m } } { 2 } \left[ \mathrm { x } ^ { 2 } \right] _ { 0 } ^ { 3 / 2 } = 98 m\frac { 9 } { 8 } \mathrm {~m}

As given 98 m\frac { 9 } { 8 } \mathrm {~m} = 12\frac { 1 } { 2 } (398)\left( \frac { 39 } { 8 } \right) ̃ m = 13/6