Question

if $y=\int\frac{e^{\tan x}dx}{\cos^2x(1+e^{2\tan x})}$ and y(0)=6 then y$\frac{\pi}{4}$ is equal to

• A. tan-1e-$\frac{\pi}{4}$
• B. tan-1e+6-$\frac{\pi}{4}$
• C. tan-1e-6+$\frac{\pi}{4}$
• D. tan-1$\frac{1}{e}$-6+$\frac{\pi}{4}$

Answer 1

Answer: (B)

tan-1e+6-$\frac{\pi}{4}$

Answer 2

The Correct answer is option is (B) : tan-1e+6-$\frac{\pi}{4}$