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Question: If y = \(\frac{x + c}{1 + x^{2}}\)where c is a constant, then when y is stationary, xy is equal to –...

If y = x+c1+x2\frac{x + c}{1 + x^{2}}where c is a constant, then when y is stationary, xy is equal to –

A

½

B

¾

C

5/8

D

None

Answer

½

Explanation

Solution

Q dydx\frac{dy}{dx} = 0 ⇒ y + x2y = x + c

dydx\frac{dy}{dx} + x2dydx\frac{dy}{dx} + y(2x) = 1 ; ∴ xy = ½