Question
Question: If y = \(\frac{x + c}{1 + x^{2}}\)where c is a constant, then when y is stationary, xy is equal to –...
If y = 1+x2x+cwhere c is a constant, then when y is stationary, xy is equal to –
A
½
B
¾
C
5/8
D
None
Answer
½
Explanation
Solution
Q dxdy = 0 ⇒ y + x2y = x + c
dxdy + x2dxdy + y(2x) = 1 ; ∴ xy = ½