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Question: If \(y = f(x)\) be monotonically decreasing or decreasing function of x and M is the median of varia...

If y=f(x)y = f(x) be monotonically decreasing or decreasing function of x and M is the median of variable x , then the median of y is
A f(M)f(M)
B M2\dfrac{M}{2}
C f1(M){f^{ - 1}}(M)
D None of these

Explanation

Solution

As it is given that the function is be monotonically decreasing or decreasing function so let us suppose that (x1,y1),(x2,y2)................(xn,yn)\left( {{x_1},{y_1}} \right),\left( {{x_2},{y_2}} \right)................\left( {{x_n},{y_n}} \right) be the coordinate of the function which is satisfy the y=f(x)y = f(x) hence if we consider function is increasing then x1<x2<.....<M<.......<xn{x_1} < {x_2} < ..... < M < ....... < {x_n} so the median of variable y is the value of function at the median . Similarly of decreasing function

Complete step-by-step answer:
In this question we have to find out the median of y where y=f(x)y = f(x) be monotonically decreasing or decreasing function of x and M is the median of variable x is given
So first let us consider that the function is monotonically decreasing and (x1,y1),(x2,y2)................(xn,yn)\left( {{x_1},{y_1}} \right),\left( {{x_2},{y_2}} \right)................\left( {{x_n},{y_n}} \right) be the coordinate of the function which is satisfy the y=f(x)y = f(x)
As we consider that the function is monotonically decreasing then x1<x2<............<xn{x_1} < {x_2} < ............ < {x_n}
Then it is given that the M indicates the median of the variable x hence it is lie in the mid of this series x1<x2<............<xn{x_1} < {x_2} < ............ < {x_n} mean that ,
x1<x2<.....<M<.......<xn{x_1} < {x_2} < ..... < M < ....... < {x_n}
so for the median of variable y is the y=f(M)y = f(M) because M is the median of variable x so the Median of variable y is f(M)f(M)
So now let us consider that the function is monotonically decreasing and (x1,y1),(x2,y2)................(xn,yn)\left( {{x_1},{y_1}} \right),\left( {{x_2},{y_2}} \right)................\left( {{x_n},{y_n}} \right) be the coordinate of the function which is satisfy the y=f(x)y = f(x)
As we consider that the function is monotonically decreasing then x1>x2>............>xn{x_1} > {x_2} > ............ > {x_n}
Then it is given that the M indicates the median of the variable x hence it is lie in the mid of this series x1>x2>............>xn{x_1} > {x_2} > ............ > {x_n} mean that ,
x1>x2>.....>M>.......>xn{x_1} > {x_2} > ..... > M > ....... > {x_n}
so for the median of variable y is the y=f(M)y = f(M) because M is the median of variable x so the Median of variable y is f(M)f(M)
Hence from both increasing or decreasing the median of variable y is f(M)f(M)
So the option A is correct .

Note: A monotonically increasing function is one that increases as x does for all real x. A monotonically decreasing function, on the other hand, is one that decreases as x increases for all real x. In particular, these concepts are helpful when studying exponential and logarithmic functions.