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Question

Mathematics Question on Exponential and Logarithmic Functions

If y =$$e^{\sqrt{x\sqrt{x\sqrt{x\ldots}}}} x>1,x>1, then d2ydx2x=loge3\left. \frac{{d^2y}}{{dx^2}} \right|_{x = \log_e 3} is

A

3

B

0

C

5

D

1

Answer

3

Explanation

Solution

The correct answer is (A) : 3.