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Question: If \[y = {e^{\log \left( {{x^5}} \right)}}\] then find the value of the first derivative \[\dfrac{{d...

If y=elog(x5)y = {e^{\log \left( {{x^5}} \right)}} then find the value of the first derivative dydx\dfrac{{dy}}{{dx}}.

Explanation

Solution

We will first consider the given function of yy. We need to find the first derivative of the given function. As we know that y=elogxy = {e^{\log x}} is equal to y=xy = x, so we will use this concept here and simplify the value of function of yy. Next, find the derivative of the obtained value and hence the result.

Complete step by step solution: First, we will consider the given function y=elog(x5)y = {e^{\log \left( {{x^5}} \right)}}
Next, we have to find the derivative dydx\dfrac{{dy}}{{dx}}.
As we know that y=elogxy = {e^{\log x}} is equal to y=xy = x.
So, we will use this concept here and simplify the given expression,
Thus, we get,

y=elog(x5) y=x5  \Rightarrow y = {e^{\log \left( {{x^5}} \right)}} \\\ \Rightarrow y = {x^5} \\\

Now, we will find the derivative of the obtained expression by differentiating yy with respect to xx.
Thus, we get,

dydx=5x51 dydx=5x4  \Rightarrow \dfrac{{dy}}{{dx}} = 5{x^{5 - 1}} \\\ \Rightarrow \dfrac{{dy}}{{dx}} = 5{x^4} \\\

Here, we have applied the formula of differentiation that is, dydx=nxn1\dfrac{{dy}}{{dx}} = n{x^{n - 1}}.

Thus, the derivative of the given function is dydx=5x4\dfrac{{dy}}{{dx}} = 5{x^4}.

Note: Note: Logarithmic functions are the inverses of exponential functions. We have used the formula of differentiation dydx=nxn1\dfrac{{dy}}{{dx}} = n{x^{n - 1}} to find the derivative of the function. The exponential and logarithmic functions are inverse of each other. Differentiate the variable yy with respect to xx to find the derivative.