Question
Mathematics Question on Continuity and differentiability
If y=e3x+7, then the value of dxdyx=0 is
A
1
B
0
C
−1
D
3e7
Answer
3e7
Explanation
Solution
∵y=e3x+7⇒dxdy=3e3x+7 ∴dxdyx=0=3e3×0+7=3e7
If y=e3x+7, then the value of dxdyx=0 is
1
0
−1
3e7
3e7
∵y=e3x+7⇒dxdy=3e3x+7 ∴dxdyx=0=3e3×0+7=3e7