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Question

Mathematics Question on Continuity and differentiability

If y=e3x+7y=e^{3x+7}, then the value of dydxx=0\frac{dy}{dx} \bigg|_{x=0} is

A

11

B

00

C

1-1

D

3e73e^7

Answer

3e73e^7

Explanation

Solution

y=e3x+7dydx=3e3x+7\because y=e^{3x+7}\Rightarrow \frac{dy}{dx}=3e^{3x+7} dydxx=0=3e3×0+7=3e7\therefore \frac{dy}{dx}\bigg|_{x=0}=3e^{3\times0+7}=3e^{7}