If (y=e^{3\log(2x+1)}), then (\frac{dy}{dx}=) | Mathematics | SolveeIt

If $y=e^{3\log(2x+1)}$ , then $\frac{dy}{dx}=$

$6e^{3\log(2x+1)}$

$6\frac{e^{3\log(2x+1)}}{2x+1}$

$\frac{e^{3\log(2x+1)}}{2x+1}$

$\frac{e^{3\log(2x+1)}}{3(2x+1)}$

$(2x+1)e^{3\log(2x+1)}$

Answer

$6\frac{e^{3\log(2x+1)}}{2x+1}$

Explanation

The correct option is (B) : $6\frac{e^{3\log(2x+1)}}{2x+1}$

Mathematics Question on Logarithmic Differentiation