Question
Mathematics Question on Ellipse
If y=2x3−2x2+3x−5, then for x=2 and Δx=0.1 value of Δy is:
A
(A) 2.002
B
(B) 1.9
C
(C) 0
D
(D) 0.9
Answer
(B) 1.9
Explanation
Solution
Explanation:
Given:y=2x3−2x2+3x−5⇒dydx=6x2−4x+3⇒(dydx)x=2=24−8+3=19∵Δy=(dydx)x=2Δx⇒Δy=19×(0.1)=1.9Hence, the correct option is (B).