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Question: If [x<sup>2</sup>] + x − a = 0 has a solution where a ∈ N and a ≤ 20, then total number of different...

If [x2] + x − a = 0 has a solution where a ∈ N and a ≤ 20, then total number of different values of 'a' can be

A

2

B

3

C

4

D

6

Answer

4

Explanation

Solution

[x2] + x − a = 0 ⇒ 'x' has to be an integer.

⇒ a = x2 + x = x(x + 1).

Thus 'a' can be 2, 6, 12, 20