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Question: If *x*<sup>2</sup> – (a – 3) *x* + a = 0 has at least one positive root, then –...

If x2 – (a – 3) x + a = 0 has at least one positive root, then –

A

a Ī (–, 0) Č [7, 9]

B

a Ī (–, 0) Č [7, )

C

a Ī (–, 0] Č [9, )

D

None of these

Answer

a Ī (–, 0] Č [9, )

Explanation

Solution

x2 – (a – 3) x + a = 0,

D = (a – 3)2 – 4a = a2 – 10a + 9

D ³ 0 Ž (a – 9) (a – 1) ³ 0

Ž a Ī (–, 1] Č [9, )

Case 1 : When both roots are positive

D ³ 0 Ž (a – 9) (a – 1) ³ 0

Ž D ³ 0, a > 0, a > 3 Ž a Ī [9, ) …(1)

Case 2 : When exactly one root is positive

Ž a £ 0 …(2)

Thus, from (1) and (2), a Ī (–, 0] Č [9, ).

Hence (3) is correct answer.